A6.0 m wire carries a current of 7.0 a toward the +x direction. a mag- netic force of 7.0 × 10−6 n acts on the wire in the −y direction. find the magnitude and direction of the magnetic field producing the force.

1) Magnitude

The magnetic force acting on a current-carrying wire is

where
I is the current
L is the length of the wire
B is the intensity of the magnetic field
is the angle between the direction of the current and the direction of the magnetic field.

In our problem, the current and the force are perpendicular to each other, this means that B is perpendicular to I as well, so this angle is  and so , so we can ignore it in the formula and rewrite it as

which can be rewritten as

and by using the data of the problem, we find the intensity of the magnetic field:


2) Direction

we can find the direction of the magnetic field by using the right-hand rule. Let's assign one vector to each finger:
index finger --> I
middle finger --> B
thumb --> F
if we take the index finger (I) in the x+ direction and the thumb (F) in the y- direction, we find that the middle finger (B) is in the z+ direction, so this is the direction of the magnetic field.

Velocity=total displacement/timefrom house to store is 500 from store to neighbor is 200 therefore total displacement=500+200=700metrestherefore,700metres/910seconds=0.8metres per second