Moving 2.0 coulombs of charge at constant speed a distance of 6.0 meters from point a to pointb within a uniform electric field requires a 5.0-newton force. what is the electric potentialdifference between points a and b?

The force produced on a particle of charge q by an electric field of intensity E is

in our problem, the force is F=5.0 N while the charge is q=2.0 C, so we can find the intensity of the electric field:


The relationship between electric field intensity and potential difference  between two points A and B is

where d is the distance between the two points. By using d=6.0 m, we find

where the negative sign means that the initial point, VA, is at higher potential than the final point VB.

Sound energy is produced when an object vibrates. examples are 1- a balloon popping2-a whistle3- a waterfall

From negative to negative