If you are pushing on a box with a force of 20 n and there is a force of 7 n on the box due to sliding friction, what is the net force on the box? i need the answer asap!

Net force acting on the box,

Explanation:

It is given that,

Force with which the box is pushed, F = 20 N

Force acting due to sliding friction, f = 7 N

Sliding friction is a type of resistive force. It always opposes the motion of an object. Here, the force of 7 N will act in the opposite direction of motion. As a result, the net force acting on the box is given by :

So, the net force acting on the box is 13 N. Hence, this is the required solution.

i'm on my way to history not a mistory.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2