At the earth's surface a projectile is launched straight up at a speed of 8.9 km/s. how many meters will it rise? ignore air resistance and the rotation of the earth.

height=4037.2km

Explanation:

Initial velocity = 8.9km/s = 8900m/s

Final velocity (maximum height) = 0

Assume gravity is constant 9.81 m/s^2 downward.

vf²=vi²+2×a(x-xi)

0=8900²-2×9.81*(height)

-2×9.81*(height)=-79210000

height=-79210000/2×9.81

height=4037206.9m

height=4037.2km  

he . if i may ask what i your question exactly?

explanation:

490 n

f=125n a=2.5m/s2