P=1/2kx^ If the spring constant is 25600 N/m. How much must thr spring stretch in meters in order to store 8J of potential energy?

Extension, x = 0.025m

Explanation:

Given the following data;

Spring constant = 25600 N/m

Potential energy = 8 Joules

To find the extension;

Mathematically, the potential energy stored in a spring is given by the formula;

Where;

Substituting into the equation, we have;

Cross-multiplying, we have;

Extension, x = 0.025m

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explanation:

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