An electron moves horizontally across the earth’s equator at a speed of 2. 50 x 106 m/s and in a direction 35. 08 n of e. At this point, the earth’s magnetic field has a direction due north, is parallel to the surface, and has a value of 3. 00 x 10-5 t. What is the force acting on the electron due to its interaction with the earth’s magnetic field?.