Mrs. Jukes decided to have a tug of war competition with the 5th grade class. Mrs. Jukes is on one side of the rope and the 5th grade class is on the other side of the rope. If Mrs. Jukes pulls the rope with 50N of force and the 5th grade class pulls the rope with 150N force, what is the net force on the rope?

100 N

Explanation:

Given that,

The force acting on the rope By Mrs. Jukes = 50 N

The 5th grade class pulls the rope with 150 N force

We need to find the net force on the rope. As two forces are acting in the opposite direction. The net force is given by :

F = 50 N - 150 N

= -100 N

Hence, the net force is 100 N.

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