Y= x2 − 6x + 8
2y + x = 4
the pair of points representing the solution set of this system of equations is and .

Some operators are missing.If the right equations are y = x^2 -6x +8 and 2y + x =4This is the solution
2y + x = 42y = -x +4y = -x/2 + 2
y = x^2 -6x + 8 = -x/2 + 2
2x^2 - 12x + 16 = -x + 42x^2 -11x +12 = 0
Factor
(x-4)(2x-3)=0
x= 4 and x =3/2
y = -x/2 +2 y = -4/2 + 2 = 0y = - (3/2)/2 + 2 = -3/4 + 2 = 5/4
Answer (4,0) and (3/2, 5/4)

Dis the correct answer