In laci —mutant cells, when there are high levels of glucose present but no lactose, how much β-galactosidase will be produced? see section 18.2 (page 371) . view available hint(s) in laci —mutant cells, when there are high levels of glucose present but no lactose, how much β-galactosidase will be produced? see section 18.2 (page 371) . a low amount a great deal it depends on what other sugars are present in the growth medium. essentially none

Option D, Essentially none

Explanation:

The essential condition for lac operon to express its subsequent proteins i.e laz A, lacZ and lacY are as follows –  

a)Absence of glucose

b)Presence of Lactose.  

In fact absence of glucose is must. In case when lactose is absent and glucose is present then the lac z sub-protein whose product is  β-galactosidase is not expressed. In fact in lac z breaks down lactose into glucose and galactose in absence of glucose.  

Hence, option D is correct

this protocol provides a detailed procedure for total protein extraction for western blot analysis from achieved samples following trizol isolation of rna.

the two answers are a, the population of birds with large beaks will increase on the island, and c, the trait for large beaks will be passed on to future generations through natural selection. the reason for that is because if the birds that have beaks developed for eating small seeds lose all of their food, they will go hungry and eventually starve because they physically cannot eat the large seeds, therefore making the population of large beaked birds higher. also, if the trait of large beaks are dominant on the island over small beaks, then over time the large beaked birds will reproduce more and more, while the smaller beaked birds will reproduce less and less because they can't survive with the food provided. that leads to the trait of small beaks disappearing and the trait of large beaks taking over the island.