This problem has been solved! see the answerin sheep, coat color is influenced by two genes. gene a influences pigment production, while gene b produces black or brown pigment. if two heterozygous white sheep were crossed and offspring were produced in a ratio of 12 white sheep to 3 black sheep to 1 brown sheep, what are the genotypes of the offspring?

White: A---

Black: aaB-

Brown: aabb

Explanation:

As per given information, the genotype of parent white sheep is AaBb (heterozygous white).

The gene "A" is dominant over gene "B". Hence, all the genotypes with one or two copies of "A" would exhibit white phenotype.

All the genotypes that have "aa" and one or two "B" alleles would exhibit black phenotype.

All the genotypes with "aabb" allele combination would exhibit brown phenotype.

try using substitution:

x + y - 6 = x - y. (i'm not giving you the exact answer). since 0 = x - y, then sub 0 in the equation with x - y. combine your like terms, and then use inverse operations, and you'll have your answer.

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what subject is this