What coefficients must be placed in the following blanks so that all atoms are accounted for in the products?
c6h12o6 -> c2h6o + co2
a. 2; 1 c. 1; 3
b. 3; 1 d. 2; 2

d. 2; 2

Explanation:

To know the coefficients to draw in front of each substance, you need to balance this chemical equation.

C6H12O6 -> C2H6O + CO2

You need to count the number of atoms in the beginning, and the products and you had to have the same amount.

First, you need to know the pair that get reduced and the pair that gets oxidated.

C6H12O6 → 6CO2 + 24e- (Oxidated)

C6H12O6 + 12e- → 3C2H6O (Reduced)

You need to equilibrate all oxygens with whater and the electrons with hidrogen

C6H12O6 + 6H2O → 6CO2 + 24e- + 24H+

C6H12O6 + 12e- + 12H+ → 3C2H6O + 3H2O

An then you sum all together to take out all the exceced atoms.

C6H12O6 → 2CO2 + 2C2H6O

That's the balanced equation.

Coefficients: 0, 2, and 2.

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