The haploid human genome contains about 3 × 109 nucleotides. on average, how many dna fragments would be produced if this dna was digested with restriction enzyme psti (a 6-base cutter)? rsai (a 4-base cutter)? how often would an 8-base cutter cleave?
i'm looking for how to work the problem, not just the answer. my guess, to start, is:
4 nucleotides, 6-base cutter; 46 = 4096
( 3x109 ) / 4096 = 73,2421.875
pstl would have aprox. 73k fragments?
Answers: 3
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The haploid human genome contains about 3 × 109 nucleotides. on average, how many dna fragments woul...
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