In sheep, the allele for belly fur (A) is dominant to the allele for no belly fur (a). A mother with the genotype As and the father with the genotype As produce an offspring. What is the percent chance the offspring with have no belly fur

25%

Explanation:

In sheep, the allele for belly fur (A) is dominant to the allele for no belly fur (a). A mother with the genotype Aa and a father with the genotype Aa produce an offspring. What is the percent chance that the offspring will have NO belly fur?

Allele A is dominant over allele a.

Genotype of mother = Aa

Genotype of father = Aa

Crossing Aa and Aa:

Aa   x   Aa = AA, 2Aa, and aa

Since A is dominant over a, both AA and Aa have belly fur.

Hence, the ratio of the offspring with belly fur to those without belly fur is 3:1.

Percentage of the offspring without belly fur is 25%.

the correct option is option a