What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K?
Use P V equals n R T. and R equals 8.314 StartFraction L times kilopascals over moles time K EndFraction..
0.715 kPa
2.45 kPa
28.2 kPa
62.7 kPa

Pressure, P = 28.2 kPa

Explanation:

Given that,

Number of moles, n = 0.54 mol

Volume of ideal gas, V = 35.5 L

Temperature, T = 223 K

We need to find the pressure of ideal gas. The equation of ideal gas is given by :

R is gas constant

P is pressure

So, the pressure of the gas is 28.2 kPa.                              

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explanation:

hydrogen is a compound or a single element and a element is a pure substence that cannot be separated into simpler subtances

clorine is a compound its a chemical substance that forms when two or more different elements combine

so both hydrogen and clorine are compounds