If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the refrigerator if it released 483j of energy to the room?

According to the second law of thermodynamics, we understand that we cannot move heat from a reservoir at a lower temperature to that of a higher temperature without providing work.

When applied to a refrigeration system, the coefficient of performance can be derived as
COPr=1/(Th/Tl-1)   where
Th=high temperature reservoir (room temperature) = 20C = 293K
Tl=low temperature reservoice (freezer compartment) = -18C=255K
=>
COPr=1/(293/273-1)=6.71

But COPr is also equal to Ql/Win,
Ql=energy removed from freezer  (to be found)
Win=work input, also equals heat energy transformed from work into the room
= 483J
=>
Ql=COPr*Win=6.71*483=3241J
3241 J are removed from food inside refrigerator (through the freezer compartment).