Consider the following timeline detailing a stream of cash flows: the timeline starts at date 0 and ends at date 4. the cash flow on date 0 is indicated by a question mark. on date 1, the cash flow is 5,000 dollars. on date 2, the cash flow is 6,000 dollars. on date 3, the cash flow is 7,000 dollars. on date 4, the cash flow is 8,000 dollars. if the current market rate of interest is 10%, then the present value (pv) of this stream of cash flows is closest to:

Present value= $20,227.45

Explanation:

Giving the following information:

On Date 1, the cash flow is 5,000 dollars. On Date 2, the cash flow is 6,000 dollars. On Date 3, the cash flow is 7,000 dollars. On Date 4, the cash flow is 8,000 dollars. The current market rate of interest is 10%.

We need to use the following formula:

PV= FV/(1+i)^n

Date 1= 5,000/1.10= 4,545.46

Date 2= 6,000/1.10^2= 4,958.68

Date 3= 7,000/1.10^3= 5,259.20

Date 4= 8,000/1.10^4= 5,464.11

Total= $20,227.45

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if kj of heat is transferred o 1200 g liquid water at 36'c, what would the new temperature of the water be? (he specific heat capacity of liquid water is 4.186 j/g''c)

a. 15'c

b.100'c

c.51'c

d.36'c