What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall redox equation: 5 ag (aq) +mn2 (aq) +4h20()5ag(s)+ mno4 (aq) +8h' (aq) a. 1 b. 2 c. 3 d. 5 ( e.?

             5 moles of electrons

Explanation:

The balance equation is as follow,

                   5 Ag⁺ + Mn⁺² + 4 H₂O    →    5 Ag + MnO₄⁻ + 8 H⁺

Reduction of Ag:

                         Ag⁺ + 1 e⁻    →    Ag
Or,
                         5 Ag⁺  +  5 e⁻    →    5 Ag

Oxidation of Mn:

                          Mn⁺²   →    MnO₄⁻  +  5 e⁻

Result:
          Hence 5 moles of Ag⁺ accepts 5 electrons from 1 mole of Mn⁺².

Just took the quiz on edgenuity and the correct answer is "c.  4.54 x  10–12  j"

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