Agas occupies 3.5 l at standard presure. find the volume of the gas when the pressure is 1140 mm hg

According to Boyle's Law, " the pressure of gas is inversely related to applied pressure at constant temperature".

For the initial and final state of pressure and volume for a given gas at given temperature is as,

                                           P₁ V₁  =  P₂ V₂          (1)
Data Given;

                  P₁  =  760 mmHg (standard Pressure)

                  P₂  =  1140 mmHg

                  V₁  =  3.5 L

                  V₂  =  ?

Solving equation 1 for V₂,

                                           V₂  =  P₁ V₁ / P₂
Putting values,
                                           V₂  =  (760 mmHg × 3.5 L) ÷ 1140 mmHg

                                           V₂  =  2.33 L
Result:
           Hence, with increase in pressure from 760 mmHg to 1140 mmHg the volume has decreased from 3.5 l to 2.33 L.

Dissociation then hydration dissolving