Consider the reaction n2 + 3 h2 → 2 nh3 . how much nh3 can be produced from the reaction of 74.2 g of n2 and 14.0 moles of h2? 1. 1.26 × 1025 molecules 2. 1.59 × 1024 molecules 3. 3.19 × 1024 molecules 4. 5.62 × 1024 molecules 5. 1.69 × 1025 molecules

Reaction:   N₂   +   3 H₂   →   2 NH₃  

the mole ratio of  H₂  :   NH₃    is    3  :   2

If the number of moles of H₂ is 14.0 mol
    then the number of moles of NH₃ = (14.0 mol ÷  3) × 2
                                                            =  9.33 mol

Now, the number of molecules = moles  ×  Avogadro's Constant
                                                     =  9.33 mol × (6.02 × 10²³)
                                                     =  5.6187 × 10²⁴  molecules

As such the answer is 5.62 × 10²⁴  molecules [OPTION 4]       
                                                                

The answer is b because a,c,and d are opinons