What volume of a 0.580-m solution of cacl2 contains 1.28 g solute?

Answer : 19.9 mL

Explanation : We have the moles of Calcium chloride and the weight of it as 1.28 g,

Here, molarity has to be related with the volume so, 0.580 M = 0.580 mol/L

so now in 1.28 g there will be : 1.28 X (1 g / 111 mol of calcium chloride) = 0.01153 mol

Now, we can find out the volume from this;

0.01153 mol X (1 L / 0.580 mol) X (1000 mL / 1 L) = 19.9 mL

Hence, the volume will be 19.9 mL

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