Potassium chloride, kcl, sodium sulfate, na2so4, glucose, c6h12o6, carbon dioxide, co2 and ammonium phosphate, (nh4)3po4, are soluble in water. which one produces the largest number of dissolved particles per mole of dissolved solute? (nh4)3po4 c6h12o6 kcl

Hello!

The solute that produce the largest number of dissolved particles per mole of dissolved solute is Ammonium Phosphate (NH₄)₃PO₄

Explanation:

When a solute is dissolved in water, it is surrounded by water molecules in a process called solvation.

Ionic solutes dissociate following the general equation showed below:

AnBm(s) → nA⁺(aq) + mB⁻(aq)

The number of particles formed will be given by the sum of n+m. So, the solute with the highest sum of n+m is Ammonium Phosphate (NH₄)₃PO₄ in which the sum equals 4

(NH₄)₃PO₄(s)→3NH₄⁺(aq) + PO₄⁻³

Have a nice day!

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.