What is the mass of 2.56 × 10–4 moles of fe2o3? : 6.23 × 105 159.6 g 1.60 × 0–6 g 4.09 × 10–2 g

4.09 × 10⁻² g

Solution:

As we know that,

1 mol of Fe₂O₃ is equal to = 159.69 g

So,

2.56 × 10⁻⁴ mol will be equal to = X g

Solving for X,

X = (159.69 g × 2.56 × 10⁻⁴ mol) ÷ 1 mol

X = 0.04088 g

Or,

X = 0.049 g

Or,

X = 4.09 × 10⁻² g

a. patterns can explain observations.

i have no clue hope you find the answer