Astudent collects 285 ml of o2 gas at a temperature of 15°c and a pressure of 0.983 atm. the next day, the same sample occupies 292 ml at a temperature of 11°c. what is the new pressure of the gas? 0.946 atm 1.00 atm 0.704 atm

According to the combined gas laws,

Plugging in the values and solving for the final pressure:

Final pressure

-

0.946 atm

Explanation:-

From the question we see,

First day pressure P 1 = 0.983 atm

First day temperature T 1 =15 C + 273 = 288 K

First day volume V 1 =285 mL

Second Day volume V 2 = 292 mL

Second day Temperature T 2 = 11 C + 273 = 284 K

Using the relation

P 1 V 1 / T 1 = P 2 V 2 / T 2

We get Second Pressure P 2 = P 1 V 1 T 2 / ( T 1 V 2)

= 0.983 atm x 285 mL x 284 K / ( 288 K x 292 mL)

= 0.946 atm

Hence the new pressure of the gas on the second day is 0.946 atm

the ratio of the conjugate base to the acid required to attain the desired ph.

they are all solids.