Calculate the mass percent of a nacl solution in which 199 g of nacl is dissolved in 2.74 l of water at 25 ∘c (density = 0.997 g/ml).

Hey there!

mass of solvent :

volume in mL => 2.74 * 1000 => 2740 mL

D = m / V

0.997 = m / 2740

m = 0.997 * 2740

m = 2731.78 g of solvent

Therefore :

T % = ( mass solute / mass solute + mass solvent ) * 100

T% = ( 199 / 199 + 2731.78 ) * 100

T% = ( 199 / 2930.78 ) * 100

T% = 0.0679 * 100

T = 6.79 % of NaCl

hope this helps!

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation: