Chemistry, 12.07.2019 18:00 maheshwarlall
He pka values of a compound with two ionizable groups are pk1 = 4.10 and pk2 between 7 and 10. a biochemist has 10 ml of a 1.0 m solution of this compound at a ph of 8.00. she adds 10.0 ml of 1.00 m hcl, which changes the ph to 3.20. what is pk2?
Answers: 1
![pH = pk_a+ log \frac{[A^{-}]}{[HA]}](/tpl/images/0081/8142/50125.png)
is:![pH = pk_1+ log \frac{[A^{-}]}{[HA]}](/tpl/images/0081/8142/76eb5.png)
![3.2 = 4.1 + log \frac{[A^{-}]}{[HA]}](/tpl/images/0081/8142/89743.png)
![log \frac{[A^{-}]}{[HA]} = - 0.9](/tpl/images/0081/8142/41786.png)
![\frac{[A^{-}]}{[HA]} = 0.126](/tpl/images/0081/8142/5103f.png)
![pH = pk_2+ log \frac{[A^{-}]}{[HA]}](/tpl/images/0081/8142/126cd.png)
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He pka values of a compound with two ionizable groups are pk1 = 4.10 and pk2 between 7 and 10. a bio...
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