In a constant pressure calorimeter experiment a student measures a temperature change of 2.5 degrees c. the heat measured was 2.200 kj. what was the volume of the solution? assume that csol=4.18 j/gc

The volume of the solution was 210 mL.

q = mCₛₒₗΔT

m = q/(CₛₒₗΔT) = 2200 J/(4.18 J·°C⁻¹g⁻¹ × 2.5 °C) = 210 g  

If the solution has the same density as water (1.00 g·mL⁻¹) ,

Volume = 210 g × (1 mL/1.00 g) = 210 mL

Note: The answer can have only two significant figures because that is all you gave for the temperature change.

i think the answer is terrae but not 100 percent sure. ▓▬▬ §