At a constant pressure and a temperature of 280 k the gas in a cylinder has a volume of 10.0 l. if the volume of the gas is increased to 20.0 l what is the new temperature 28 k 560 k 140 k 2800 k

At constant pressure a known moles of gas has volume which is directly proportional to temperature (Charle's Law)

Thus V α T

Therefore

V1/V2 = T1 /T2

V1 = initial volume = 10 L

T1 = initial temperature= 280 K

V2 = final volume = 20L

T2 = final temperature = ?

T2 = T1V2 / V1 = 280 X 20 / 10 = 560 K

Thus the new temperature will also doubles up as volume is increased by two times

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.