Give the spectator ions for the reactions that occur when aqueous solutions of h2so4 and koh are mixed. you so much.

Potassium ions and sulfate ions.

Start with the chemical equation for this reaction.

Sulfuric acid is a strong acid. Potassium hydroxide is a strong base. Acids neutralize base in aqueous environments to produce a salt and water.

That is:

Sulfuric Acid + Potassium Hydroxide → Potassium sulfate + Water

Rewrite the chemical equation as an ionic one. Take all strong electrolytes- including strong acids, strong bases, and soluble salts- apart as their comprising ions. Do not take water molecules apart. As a weak electrolyte, water molecules barely disassociate to produce ions.

Ions that are present on both sides of the equation by the same quantity do not take part in the net reaction. They are thus considered spectator ions.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%