Al (s) + fe2o3 (s) --> al2o3 (s) + fe (s) (needs balancing) how many grams of fe can be produced when 65.2 g of al is reacted with an excess (unlimited) supply of fe2o3?

134.967 grams of Fe will be produced when 65.2 g of Al is reacted with an excess (unlimited) supply of .

Solution:

Given :

After balancing,

As we are given is in excess. Hence, Al will be considered as limiting reagent because it limits the formation of product.

According to reaction ,2 moles of reacts with one mole of to give 2 moles of Fe then 2.4166 moles of will give :

Mass of produced =

134.967 grams of Fe will be produced when 65.2 g of Al is reacted with an excess (unlimited) supply of .

the answer would be c

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