How many moles of ba(no3)2 are there in 0.25 l of a 2.00 m ba(no3)2 solution? 0.13 mol 0.50 mol 2.25 mol 8.0 mol

Answer : The number of moles present in barium nitrate solution is, 0.50 moles

Solution : Given,

Molarity of barium nitrate solution = 2 M = 2 mole/L

Volume of solution = 0.25 L

Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.

Formula used :

or,

Now put all the given values in this formula, we get the moles of barium nitrate.

Therefore, the number of moles present in barium nitrate solution is, 0.50 moles

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