Brainliestttme : )
lithium has a 1+ charge, and oxygen has a 2− charge. a lewis dot diagram should contain one lithium atom and two oxygen atoms to show how these atoms form an ionic bond.
true
false

Answer : False, there will be two lithium and one oxygen atoms in a unit molecular structure of lithium oxide.

Explanation:

Electronic configuration of lithium is :

In order to attain stable electronic configuration it will loose an electron and form positively charge cation.

The electronic configuration of oxygen is:

Oxygen being second most electronegative atom requires two electrons to attain noble gas configuration stability and form negatively charge ion with 2- charge.:

When two atom of lithium and oxygen comes together , one electron from each lithium atom get transferred to an oxygen atom which results in formation of lithium oxide.

HELLO :)

The answer would be false because the Lewis plot should contain 2 lithium atoms & 1 oxygen atom.

Since the lithium atom only contains 1 valence electron, then it wouldn't be enough to fill the valence shell of the oxygen atom because the oxygen only has 6 valence electrons in its valence shell. So it needs one more, that why it would need 2 lithium atoms.

hope this helps :P

a graduated cylinder.

explanation:

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol