Determine the molar mass of a 0.458 gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm. show work.
!

9.165 g/mol.

Explanation:

PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the container in L.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas in K.

∵ n = mass/molar mass.

∴ PV = (mass/molar mass)RT

∴ molar mass = (mass/PV)*(RT)

∵ m = 0.458 g, R = 0.082 L.atm/mol.K, P = 0.98 atm, V = 1.20 L, T = 287 K.

∴ molar mass = (mass/PV)*(RT) = (0.458 g/(0.98 atm)(1.20 L))*(0.082 L.atm/mol.K)(287 K) = 9.165 g/mol.

its first and third is your answer i did the qustion the fourth isnt right