Calculate the molarity of a solution in which 212.5g of nano3 are contained in 3.0 liters of solution.

Molarity's formula is: moles solute/liters solution.

In this question, we are given grams of solute so we have to convert that to moles.

NaNO3 has a molar mass of 84.9947g/mol. Here we begin with the given 212.5g and multiplying it by 1mol/84.9947g because the grams have to cancel out to give moles.

Now that we have moles of solute, we just plug it into the formula.

2.5 mols NaNO3/3L solution=0.8333 M of solution

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