What is the molarity of a solution prepared by dissolving 20.0 grams of naoh in sufficient water to make a solution with a total volume of 2.40 liters?
0.120 m naoh
0.208 m naoh
0.416 m naoh
0.833 m naoh

0.208 M NaOH.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of NaOH/(V of the solution (L)).

∴ M of NaOH = (20.0 g / 40.0 g/mol)/(2.4 L) = 0.2083 M ≅ 0.208 M.

B 0.208 M NaOH

Explanation:

Took the test

58750.08068 is the answer i think

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