Chemistry, 13.08.2019 05:30 naysia2006

Deduce the formulas of the following ionic compounds: (a) iron(lll) sulfide, (b) mercury(ll) nitrate, and (c) potassium sulfite.

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Answer from: babygirl1780

For a: The chemical formula for Iron (III) sulfide is Fe_2S_3

For b: The chemical formula for mercury (II) nitrate is Hg(NO_3)_2

For c: The chemical formula for potassium sulfite is K_2SO_3

Explanation:

All the given compounds are ionic compounds. This means that between the atoms complete sharing of electrons takes place.

For a:

Iron is the 26th element of periodic table having electronic configuration of [Ar]3d^64s^2 .

To form $Fe^{3+}$ ion, this element will loose 3 electrons.

Sulfur is the 16th element of periodic table having electronic configuration of [Ne]3s^23p^4 .

To form $S^{2-}$ ion, this element will gain 2 electrons.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfide is Fe_2S_3

For b:

Mercury is the 80th element of periodic table having electronic configuration of $[Xe]4f^{14}5d^{10}6s^2$ .

To form $Hg^{2+}$ ion, this element will loose 2 electrons.

Nitrate ion is a polyatomic ion having chemical formula of $NO_3^{-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for mercury (II) nitrate is Hg(NO_3)_2

For c:

Potassium is the 19th element of periodic table having electronic configuration of [Ar]4s^1 .

To form $K^{+}$ ion, this element will loose 1 electron.

Sulfite ion is a polyatomic ion having chemical formula of $SO_3^{2-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for potassium sulfite is K_2SO_3

Answer from: Quest

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

Answer from: Quest

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

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Deduce the formulas of the following ionic compounds: (a) iron(lll) sulfide, (b) mercury(ll) nitrat...