Asmall cubical furnace 50 by 50 by 50 cm on the inside is constructed of fireclay brick [k = 1.04 w/m. degree c] with a wall thickness of 10 cm. the inside of the furnace is maintained at 500 degree c, and the outside is maintained at 50 degree c. calculate the heat lost through the walls.

Q=1170J/s = 279.516cal/s

Explanation:

q=-k.(T₀-T₁)/(x₀- x₁)

q= heat flow density

T= temperature

x= thickness

q= -(1.04 W/m. ºC) . (50ºC-500ºC)/(0.1m-0m)

q=4680W/m²=4,68KW/m²

1KW=1000J/s

∴ q= 4680 J/s.m²

q= Q/A

Q=heat fluw

A= surface= 6 . (0.5m . 0.5m)= 0.25m²

Q= (4680J/s.m²) . (0.25m²)

Q=1170J/s = 279.516cal/s

1J=0.2389cal

i believe the answer is true.

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.