The decomposition of 3.32 g caco3 yields 1.24 g cao. what is the percent yield of this reaction? (caco3 --> cao + co2)

66.57%

Explanation:

The decomposition reaction of calcium carbonate is shown below as:

Calculation of moles of :

Amount = 3.32 g

Molar mass of = 100 g/mol

The formula for the calculation of moles is shown below:

Thus, moles are:

According to reaction,

0.0332 moles of decomposes to yield 0.0332 moles of

Theoretical yield = 0.0332 moles

Calculation of moles of formed as:

Amount = 1.24 g

Molar mass of = 56 g/mol

The formula for the calculation of moles is shown below:

Thus, moles are:

Experimental yield = 0.0221 moles

Thus,

Percent yield = 66.57%

a:

by the combination of an unlimited number of elements