How much energy is released by the decay of 3 grams of 230th in the following reaction 230 th - 226ra + "he (230 th = 229.9837 g/mol, 226ra = 225.9771 g/mol, "he = 4.008 g/mol) (10 pts.)

The energy released for the decay of 3 grams of 230-Thorium is

Explanation:

First we have to calculate the mass defect .

The equation for the alpha decay of thorium nucleus follows:

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

(Conversion factor: )

To calculate the energy released, we use Einstein equation, which is:

The energy released for 230 grams of decay of thorium is

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of =

Then, 3 grams of Th will release energy of =

Hence, the energy released for the decay of 3 grams of 230-Thorium is

the answer is d.) potassium