How much heat, in joules and in calories, must be added to a 75.0- g iron block with a specific heat of 0.449 j/g degree cecius to increas its temperature from 25 degree celcius to its melting temperature of 1535 dgree celcius?

The heat required by iron is 50849.25 Joules or 12152.97 Cal.

Explanation:

To calculate the amount of heat released or absorbed, we use the equation:

where,

q = heat absorbed

m = mass of iron = 75 g

c = specific heat capacity of iron = 0.449 J/g.°C

= change in temperature =

Putting values in above equation, we get:

Converting the value from joules to calories, we use the conversion factor:

1 J = 0.239 Cal

So,

Hence, the heat required by iron is 50849.25 Joules or 12152.97 Cal.

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa

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