Air in an internal combustion engine is at 440°f and 150 psia, with a volume of 10 in3 what is the mass of air (in lbm)?

The mass of air is 0.00260 lbs.

Explanation:

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

Or,

where,

P = pressure of the gas = 150 psia = 10.2 atm   (Conversion factor:  1 psia = 0.068 atm)

V = Volume of gas =    (Conversion factor:   )

m = mass of air = ?

M = Average molar mass of air = 28.97 g/mol

R = Gas constant =

T = temperature of the gas =  (Conversion factor:  )

Putting values in above equation, we get:

Converting this mass into lbs, we use the conversion factor:

1 lbs = 454 g

So,

Hence, the mass of air is 0.00260 lbs.

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.