Nickel has an fcc structure and an atomic radius of 0.124 nm. (12 points) a. what is the coordination number? b. calculate the ape c. calculate the lattice parameter, "a" d. calculate the theoretical density

a)CN=12

b)APF=74 %

c)a=0.35 nm

d)ρ=9090.9

Explanation:

Given that

Nickel have FCC structure

We know that in FCC structure ,in FCC 8 atoms at corner with 1/8 th part in one unit cell and 6 atoms at faces with 1/2 part in one unit cell .

Z=8 x 1/8 + 1/2 x 6 =4

Z=4

Coordination number (CN)

 The number of atoms which touch the second atoms is known as coordination number.In other word the number of nearest atoms.

CN=12

Coordination number of FCC structure is 12.These 12 atoms are 4 atoms at the at corner ,4 atoms at 4 faces and 4 atoms of next unit cell.

APF

We know that for FCC

Now by putting the values

APF=0.74

APF=74 %

a=0.35 nm

Density

We know that M for Ni

M=58.69 g/mol

a=0.35 nm

ρ=9090.9

the answer would be b i believe