Be sure to answer all parts. as an epa scientist studying catalytic converters and urban smog, you want to find kc for the following reaction: 2 no2(g) ⇌ n2(g) + 2 o2(g) kc = ? use the following data to find the unknown kc: 1/2 n2(g) + 1/2 o2(g) ⇌ no(g) kc = 4.8 × 10 −10 2 no2(g) ⇌ 2no(g) + o2(g) kc = 1.1 × 10−5 kc = × 10

The equilibrium constant Kc, for the reaction 2 NO₂(g) ⇌ N2(g) + 2O₂(g) is 4.77 × 10¹³

From the question,

We are to determine the equilibrium constant, Kc for the reaction

2 NO₂(g) ⇌ N2(g) + 2O₂(g)

The equilibrium constant, Kc for this reaction is given by

From the given data,

We have that

¹/₂ N₂(g) + ¹/₂ O₂(g) ⇌ NO(g)            Kc₁ = 4.8 × 10⁻¹⁰

The equilibrium constant, Kc₁, for this reaction is given by

    --------------- (X)

Also,

2NO₂(g) ⇌ 2NO(g) + O₂(g)              Kc₂ = 1.1 × 10⁻⁵

The equilibrium constant, Kc₂, for this reaction is given by

      -------------- (Y)

Now,

From (X)

We can write that

Put this into (Y)

We get

Then,

∴

Recall that,

The equilibrium constant Kc, for the reaction 2NO₂(g) ⇌ N2(g) + 2O₂(g) is given by

∴

From the question,

Kc₁ = 4.8 × 10⁻¹⁰

Kc₂ = 1.1 × 10⁻⁵

∴

∴ Kc = 4.77 × 10¹³

Hence, the equilibrium constant Kc, for the reaction 2NO₂(g) ⇌ N2(g) + 2O₂(g) is 4.77 × 10¹³

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Kc = 4.8x10^13

Explanation:

2 NO2(g) ⇌ N2(g) + 2 O2(g)

(1) 1/2 N2(g) + 1/2 O2(g) ⇌ NO(g) Kc = 4.8 × 10 −10

(2) 2 NO2(g) ⇌ 2NO(g) + O2(g) Kc = 1.1 × 10−5

Using the 2 given reactions you need to form the asked in the first place, in order to do that you multiply one of them by 2 and switch reactants with products and then add them together

(1): 1/2 N2(g) + 1/2 O2(g) ⇌ NO(g) / x2

N2(g) + O2(g) ⇌ 2 NO(g) / switch reactants with products (equivalent to multiply by -1)

2 NO(g) ⇌ N2(g) + O2(g)

(2): 2 NO2(g) ⇌ 2NO(g) + O2(g)

Adding them you get:

2 NO(g) + 2 NO2(g) ⇌ 2NO(g) + O2(g) + O2(g)

After eliminating NO in both sides:

2 NO2(g) ⇌ 2NO(g) + O2(g)

Now that the reaction is formed, everything you multiplied to the reactions you have to do the same in the constant but in the exponent and if you add reactions you multiply each other constants, then:

Kc = (4.8 × 10 −10)^(2*(-1)) *  1.1 × 10−5 = 4.8x10^13

11 players on a field that has a maximum of 11 players

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .