Calcium hydroxide, which reacts with carbon dioxide to form calcium carbonate, was used by the ancient romans as mortar in stone structures. the reaction for this process is

ca(oh)2(s) + co2(g) --> caco3(s) + h2o(g) ; δh = -69.1 kj

what is the enthalpy change if 3.8 mol of calcium carbonate is formed?

(a) -18 kj
(b) -69 kj
(c) -73 kj
(d) -260 kj

The enthalpy change is -260 kJ.

Explanation:

Enthalpy is an extensive property, that is, it depends of the amount of matter. Let's consider the following reaction:

Ca(OH)₂(s) + CO₂(g) ⇄ CaCO₃(s) + H₂O(g)

When 1 mol of CaCO₃ is formed, 69.1 kJ of heat are released. Then, for 3.8 moles of CaCO₃,

electron microscopy and scanning tunneling microscopes gives us a greater understanding of atoms by being able to see the atom itself, and lets us see some atomic reactions.

explanation:

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.