The temperature of the cooling water as it leaves the hot engine
of a certain automobile is 244°f. after it passes through the
radiator it has a temperature of 177°f. calculate the amount of
heat (in kj) transferred from the engine to the surroundings by
one gallon of water with a specific heat of 4.1801
j/g.°c. (assume the density of water is 0.997 g/ml across the
temperature range.)

Q = 5.8 × 10²KJ

Explanation:

Given data:

Initial temperature = 177 °F (80.5556 °C)

Final temperature = 244 °F  (117.778 °C)

Mass of water = 1 gal = 3785.41 g

Specific heat of water = 4.1801 J/g.°C

Amount of heat transfer from engine to surrounding = ?

Solution:

ΔT = T2 -T1

ΔT = 117.778 °C - 80.5556 °C = 37.2224 °C

Formula

Q = m. c. ΔT

Q = 3785.41 g × 4.1801 J/g.°C × 37.2224 °C

Q = 588984.64 J

Q = 588.985 KJ

Q = 5.8 × 10²KJ

1. they vary with a higher number because boiling is way hotter than melting

warm front forms when a moist, warm air mass slides up and over a cold air mass. as the warm air mass rises, it condenses into a broad area of clouds. a warm front brings gentle rain or light snow, followed by warmer, milder weather.

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