Aflask with a volume of 3.16 l contains 9.33 grams of an unknown gas at 32.0°c and 1.00 atm. what is the molar mass of the gas?

73.88 g/mol

Explanation:

For this question we have to keep in mind that the unknown substance is a gas, therefore we can use the ideal gas law:

In this case we will have:

P= 1 atm

V= 3.16 L

T = 32 ªC = 305.15 ºK

R= 0.082

n= ?

So, we can solve for "n" (moles):

Now, we have to remember that the molar mass value has "g/mol" units. We already have the grams (9.33 g), so we have to divide by the moles:

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