Aresearcher studying the nutritional value of a new candy places a 3.80 g3.80 g sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. the observed temperature increase is 2.92 ∘c.2.92 ∘c. if the heat capacity of the calorimeter is 41.70 kj⋅k−1,41.70 kj⋅k−1, how many nutritional calories are there per gram of the candy?

Explanation:

The given data is as follows.

         Heat capacity = 41.70 kJ/K,        

Temperature change =

Hence, calculate the quantity of heat as follows.

      Quantity of heat = heat capacity × temp. change

                                  = 41.70 kJ/K × 2.92 K

                                  = 121.764 kJ

This heat energy is related to burning of 3.80 g of given sample.

Therefore, calculate the heat per gram as follows.

                  Heat =

                           = 32.04 kJ/g

As, 1 nutritional calorie = 1000 calorie

      1 calorie = 4.2 J

Therefore, calculate the heat in terms of calorie as follows.

            Heat =

                     = 7.62 calorie

Thus, we can conclude that there are 7.62 calories per gram of the candy.

n has four pairs of electrons in the valence shell, electrons repel one another ,n has 7 protons in its nucleus, and since n has 7 protons, it must fill the second shell, giving it 4 pairs of electrons. the electrons form 3 bonds and 1 lone pair of electrons. each pair of electrons repels the other pairs, so they are equally far apart.

so all of the above