What is the total pressure of the two gases collected over water at 24 degrees celsius if the pressure of hydrogen gas is 3.0kpa and the pressure of water vapor is 91.4kpa

P(total) = 94.4 kpa

Explanation:

Given data:

Pressure of hydrogen gas = 3.0 kpa

Pressure of water vapors = 91.4 kpa

Total pressure =?

Solution:

According to Dalton law of partial pressure,

The total pressure exerted by mixture of gases is equal to the sum of partial pressure of the individual gas.

This expression can be written as,

P(total) = P₁ + P₂ + P₃ + Pₙ

Now we will put the values in formula:

P(total) = P₁ + P₂

P(total) = 3.0 kpa + 91.4 kpa

P(total) = 94.4 kpa

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

bcde is the incorrect answer it is a