25 points!

phosphoric acid reacts with sodium hydroxide: h3po4(aq) + 3naoh(aq) > na3po4(aq) + 3h2o(l)if 7.50 mol h3po4 is made to react with 15.0 mol naoh, identify the limiting reagent. show all work!

Sodium hydroxide (NaOH) is the limiting reactant

Explanation:

Step 1: Data given

Number of moles of NaOH = 15.0 mol

Number of moles of H3PO4 = 7.50 mol

Molar mass of NaOH = 40 g/mol

Molar mass of H3PO4 = 98 g/mol

Step 2: The balanced equation:

H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

Step 3: Calculate the limiting reactant

For 1 mole of H3PO4, we need 3 moles of NaOH

NaOH is the limiting reactant. It will completely be consumed. (15 moles)

H3PO4 is in excess, there will react 15.0 / 3 = 5 moles

There will remain 7.5 - 5.0 = 2.5 moles

There will be produced 15.0/3 = 5.0 moles of Na3PO4

There will be produced 15.0 moles of H2O

Sodium hydroxide (NaOH) is the limiting reactant

the awnser is group 12