Arrange the following solutions in order of decreasing freezing point: 0.20 m baf2, 0.15 m c6h12, 0.10 m crbr3, 0.15 m ch3ch2ch2cooh, 0.35 m kbr. (enter just the formulas in your answer. use the appropriate < , =, or > symbol to separate substances in the list.)

0.35 m > 0.20 m > 0.10 m > 0.15 m > 0.15 m

Explanation:

For the given aqueous solutions:

dissociates to form and

For 0.20 m of , the total concentration in ions = 3*0.20 = 0.60 m

does not dissociate. Therefore, the total concentration = 0.15 m.

dissociates to form and

For 0.10 m of , the total concentration in ions = 4*0.10 = 0.40 m

dissociates to form and .

For 0.15 m of , the total concentrations of ions = 2*0.15 = 0.30 m

dissociates to for and .

Thus, for 0.35 m of KBr, the total concentration of ions = 2*0.35 m = 0.70 m

Therefore, arranging the aqueous solutions in order of decreasing freezing point:

0.35 m > 0.20 m > 0.10 m > 0.15 m > 0.15 m