1. how many grams would 8.1 x 1021 molecules of sucrose (c12h22011)
weigh?

The mass in grams of 8.1 x 10²¹ molecules of sucrose (C12H22011) is 4.62g.

HOW TO CALCULATE MASS:

= 144 + 22 + 176

= 342g/mol

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Mass = 4.6 g

Explanation:

Given data:

Number of molecules of sucrose = 8.1 ×10²¹ molecules

Mass of sucrose = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules

1.35 × 10⁻² mol

Mass of sucrose:

Mass = number of moles × molar mass

Molar mass = 342.3 g/mol

Mass = 1.35 × 10⁻² mol ×342.3 g/mol

Mass = 462.1  × 10⁻² g

Mass = 4.6 g

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